Directive Influence in Bromination of Bromobenzene

To evaluate the given statements:

1. Analysis of STATEMENT-1:
   Bromobenzene undergoes electrophilic aromatic substitution when treated with $\text{Br}_2/\text{Fe}$ (which generates $\text{FeBr}_3$ in situ as the Lewis acid catalyst to form the electrophile $\text{Br}^+$).
   The bromine atom present on the benzene ring is an ortho/para-directing group. Due to steric hindrance at the ortho-position, substitution preferentially takes place at the para-position, yielding 1,4-dibromobenzene as the major product and 1,2-dibromobenzene as the minor product.
   Therefore, STATEMENT-1 is True.

2. Analysis of STATEMENT-2:
   Halogens attached to an aromatic ring exhibit two competing electronic effects:

   • A strong electron-withdrawing inductive effect ($-I$ effect) through the $\sigma$-bond framework.

   • An electron-donating resonance/mesomeric effect ($+M$ effect) via delocalization of the lone pair of electrons on the halogen into the $\pi$-system.

   • Reactivity: The inductive withdrawal ($-I$) is stronger than the mesomeric release ($+M$), which causes net deactivation of the benzene ring toward electrophilic attack compared to benzene.

   • Directive Influence (Orientation): The incoming electrophile attacks preferentially at the ortho and para positions because the carbocation (arenium ion) intermediates formed by ortho and para attacks are uniquely stabilized by the $+M$ resonance donation of the halogen's lone pair, giving an especially stable octet-complete contributing structure. Hence, the mesomeric effect ($+M$) dominates in directing the incoming electrophile, not the inductive effect.

   Therefore, STATEMENT-2 is False.

Conclusion:
STATEMENT-1 is True, STATEMENT-2 is False.

Hence, the correct option is C.