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Determine Zero Error in Vernier Caliper Measurement

In a Vernier calipers, when both jaws touch each other, zero of the Vernier scale is shifted to the right of zero of the main scale and 7th7^{\text{th}} Vernier division coincides with a main scale reading. If the value of 1 main scale division is 1 mm1\text{ mm} and there are 10 Vernier scale divisions, then the Vernier caliper has

Options

A

0.07 cm0.07\text{ cm} negative zero error

B

0.7 cm0.7\text{ cm} negative zero error

C

0.07 cm0.07\text{ cm} positive zero error

Correct
D

0.7 cm0.7\text{ cm} positive zero error

Topics & Concepts

Step-by-Step Solution

To determine the zero error of the Vernier caliper, we calculate the Least Count (LC\text{LC}) and use the position of the Vernier scale's zero mark relative to the main scale's zero mark.

  1. Least Count (LC\text{LC}) Calculation: Given:

    • Value of 1 Main Scale Division (MSD)=1 mm=0.1 cm1\text{ Main Scale Division (MSD)} = 1\text{ mm} = 0.1\text{ cm}
    • Total number of Vernier scale divisions (NN) = 1010

    The Least Count (LC\text{LC}) of the Vernier caliper is given by: LC=1 MSDN=1 mm10=0.1 mm=0.01 cm\text{LC} = \frac{1\text{ MSD}}{N} = \frac{1\text{ mm}}{10} = 0.1\text{ mm} = 0.01\text{ cm}

  2. Sign of the Zero Error: When both jaws touch each other, the zero of the Vernier scale lies to the right of the zero of the main scale. Hence, the zero error is positive.

  3. Magnitude of the Zero Error: The positive zero error is calculated using the coinciding division of the Vernier scale: Zero Error=+(Coinciding Vernier Division)×LC\text{Zero Error} = + (\text{Coinciding Vernier Division}) \times \text{LC} Zero Error=+(7×0.01 cm)=+0.07 cm\text{Zero Error} = + (7 \times 0.01\text{ cm}) = + 0.07\text{ cm}

Therefore, the Vernier caliper has a 0.07 cm0.07\text{ cm} positive zero error.

Correct Option: C

Determine Zero Error in Vernier Caliper Measurement | Physics PYQ Solution - JEE Challenger