JEE Challenger
More from Organic Chemistry - Basic Principles

Decreasing Priority Order of Functional Groups in IUPAC Nomenclature

In IUPAC nomenclature, the correct order of decreasing priority of functional group is :

Options

A

CONH2,>C=O,CHO,NH2,CC-\text{CONH}_2, >\text{C}=\text{O}, -\text{CHO}, -\text{NH}_2, -\text{C}\equiv\text{C}-

B

CONH2,COOCH3,CHO,NH2,OH-\text{CONH}_2, -\text{COOCH}_3, -\text{CHO}, -\text{NH}_2, -\text{OH}

C

CONH2,CHO,>C=O,NH2,CC-\text{CONH}_2, -\text{CHO}, >\text{C}=\text{O}, -\text{NH}_2, -\text{C}\equiv\text{C}-

Correct
D

CONH2,CHO,CN,NH2,CC-\text{CONH}_2, -\text{CHO}, -\text{CN}, -\text{NH}_2, -\text{C}\equiv\text{C}-

Step-by-Step Solution

To determine the correct order of decreasing priority of functional groups in IUPAC nomenclature, we recall the standard IUPAC priority table for principal functional groups in decreasing order:

Carboxylic acids (COOH)>Esters (COOR)>Acid Halides (COX)>Amides (CONH2)>Nitriles (CN)>Aldehydes (CHO)>Ketones (>C=O)>Alcohols (OH)>Amines (NH2)>Alkenes (C=C)>Alkynes (CC)\text{Carboxylic acids } (-\text{COOH}) > \text{Esters } (-\text{COOR}) > \text{Acid Halides } (-\text{COX}) > \text{Amides } (-\text{CONH}_2) > \text{Nitriles } (-\text{CN}) > \text{Aldehydes } (-\text{CHO}) > \text{Ketones } (>\text{C}=\text{O}) > \text{Alcohols } (-\text{OH}) > \text{Amines } (-\text{NH}_2) > \text{Alkenes } (-\text{C}=\text{C}-) > \text{Alkynes } (-\text{C}\equiv\text{C}-)

Evaluating the given options based on this priority order:

  1. Option A: CONH2,>C=O,CHO,NH2,CC-\text{CONH}_2, >\text{C}=\text{O}, -\text{CHO}, -\text{NH}_2, -\text{C}\equiv\text{C}-

    • Incorrect, because Aldehydes (CHO-\text{CHO}) have a higher priority than Ketones (>C=O>\text{C}=\text{O}).
  2. Option B: CONH2,COOCH3,CHO,NH2,OH-\text{CONH}_2, -\text{COOCH}_3, -\text{CHO}, -\text{NH}_2, -\text{OH}

    • Incorrect, because Esters (COOCH3-\text{COOCH}_3) have a higher priority than Amides (CONH2-\text{CONH}_2), and Alcohols (OH-\text{OH}) have a higher priority than Amines (NH2-\text{NH}_2).
  3. Option C: CONH2,CHO,>C=O,NH2,CC-\text{CONH}_2, -\text{CHO}, >\text{C}=\text{O}, -\text{NH}_2, -\text{C}\equiv\text{C}-

    • Correct, because: Amide (CONH2)>Aldehyde (CHO)>Ketone (>C=O)>Amine (NH2)>Alkyne (CC)\text{Amide } (-\text{CONH}_2) > \text{Aldehyde } (-\text{CHO}) > \text{Ketone } (>\text{C}=\text{O}) > \text{Amine } (-\text{NH}_2) > \text{Alkyne } (-\text{C}\equiv\text{C}-)
  4. Option D: CONH2,CHO,CN,NH2,CC-\text{CONH}_2, -\text{CHO}, -\text{CN}, -\text{NH}_2, -\text{C}\equiv\text{C}-

    • Incorrect, because Nitriles (CN-\text{CN}) have a higher priority than Aldehydes (CHO-\text{CHO}).

Hence, the correct order is given in Option C.

Decreasing Priority Order of Functional Groups in IUPAC Nomenclature | Chemistry PYQ Solution - JEE Challenger