JEE Challenger
More from Surface Chemistry

Characteristics and Features of Adsorption Processes

The correct option(s) related to adsorption processes is(are)

Options

A

Chemisorption results in a unimolecular layer.

Correct
B

The enthalpy change during physisorption is in the range of 100100 to 140 kJ mol−1140\text{ kJ mol}^{-1}.

C

Chemisorption is an endothermic process.

D

Lowering the temperature favors physisorption processes.

Correct

Step-by-Step Solution

To determine the correct option(s) related to adsorption processes, let us analyze each statement individually:

  1. Option (A): Chemisorption results in a unimolecular layer.

    • Chemisorption involves the formation of strong chemical bonds (covalent or ionic) between the adsorbate molecules and the active sites on the adsorbent surface.
    • Once all the specific surface sites are occupied, further chemical bonding cannot occur directly with the adsorbent. Consequently, chemisorption stops at a single layer, forming a unimolecular (monolayer) surface coverage.
    • Therefore, Option (A) is correct.
  2. Option (B): The enthalpy change during physisorption is in the range of 100100 to 140 kJ mol−1140\text{ kJ mol}^{-1}.

    • Physisorption involves weak van der Waals forces of attraction. Because these interactions are weak, the enthalpy of physisorption is low, typically in the range of 20 to 40 kJ mol−120\text{ to }40\text{ kJ mol}^{-1}.
    • Higher values of enthalpy of adsorption (typically 80 to 240 kJ mol−180\text{ to }240\text{ kJ mol}^{-1}) correspond to chemisorption due to chemical bond formation.
    • Therefore, Option (B) is incorrect.
  3. Option (C): Chemisorption is an endothermic process.

    • Adsorption involves a decrease in residual attractive forces at the surface, which leads to a release of surface energy. Furthermore, gas molecules lose degrees of freedom upon adsorption, so ΔS<0\Delta S < 0.
    • For the process to be spontaneous (ΔG=ΔH−TΔS<0\Delta G = \Delta H - T\Delta S < 0), the enthalpy change ΔH\Delta H must be negative (ΔH<0\Delta H < 0). Thus, chemisorption is generally an exothermic process.
    • Therefore, Option (C) is incorrect.
  4. Option (D): Lowering the temperature favors physisorption processes.

    • Physisorption is an exothermic process at equilibrium: Adsorbate (g)+Adsorbent (s)⇌Adsorbed State+Heat(ΔH<0)\text{Adsorbate (g)} + \text{Adsorbent (s)} \rightleftharpoons \text{Adsorbed State} + \text{Heat} \quad (\Delta H < 0)
    • According to Le Chatelier's principle, lowering the temperature shifts the equilibrium in the forward (exothermic) direction, thereby increasing the extent of adsorption.
    • Therefore, Option (D) is correct.

Conclusion: The correct options are A and D.