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Calculate Value of Expression Involving Logarithmic Equations

Let a=32a = 3\sqrt{2} and b=151/66b = \frac{1}{5^{1/6}\sqrt{6}}. If x,yRx, y \in \mathbb{R} are such that 3x+2y=loga(18)54and3x + 2y = \log_a (18)^{\frac{5}{4}} \quad \text{and} 2xy=logb(1080),2x - y = \log_b \left(\sqrt{1080}\right), then 4x+5y4x + 5y is equal to _____.

Official Numerical Answer8

Step-by-Step Solution

To find the value of 4x+5y4x + 5y, we first simplify the logarithmic expressions using the definitions of aa and bb.

Given a=32=18=181/2a = 3\sqrt{2} = \sqrt{18} = 18^{1/2}, we rewrite the first equation as: 3x+2y=loga(18)5/4=loga(a2)5/4=523x + 2y = \log_a (18)^{5/4} = \log_a (a^2)^{5/4} = \frac{5}{2}

Given b=151/66b = \frac{1}{5^{1/6}\sqrt{6}}, we note that b6=1080b^{-6} = 1080, so 1080=b3\sqrt{1080} = b^{-3}. This simplifies the second equation to: 2xy=logb(b3)=32x - y = \log_b (b^{-3}) = -3

Solving the system of linear equations 3x+2y=523x + 2y = \frac{5}{2} and 2xy=32x - y = -3 yields x=12x = -\frac{1}{2} and y=2y = 2.

Finally, evaluating the required expression: 4x+5y=4(12)+5(2)=84x + 5y = 4\left(-\frac{1}{2}\right) + 5(2) = 8

Thus, 4x+5y4x + 5y is equal to 88.

Calculate Value of Expression Involving Logarithmic Equations | Mathematics PYQ Solution - JEE Challenger