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Calculate Internal Energy Change for Gas Heated at Constant Volume

55 moles of unknown gas is heated at constant volume from 10C10\,^{\circ}\text{C} to 20C20\,^{\circ}\text{C}. The molar specific heat of this gas at constant pressure cp=8 cal/molCc_p = 8\text{ cal/mol}\cdot^{\circ}\text{C} and R=8.36 J/molCR = 8.36\text{ J/mol}\cdot^{\circ}\text{C}. The change in the internal energy of the gas is \underline{\quad\quad\quad} calorie.

Official Numerical Answer300

Step-by-Step Solution

To calculate the change in internal energy of the gas, we follow these step-by-step calculations:

1. Given Data:

  • Number of moles, n=5 moln = 5\text{ mol}
  • Initial temperature, T1=10CT_1 = 10\,^{\circ}\text{C}
  • Final temperature, T2=20CT_2 = 20\,^{\circ}\text{C}
  • Molar specific heat capacity at constant pressure, Cp=8 cal/molCC_p = 8\text{ cal/mol}\cdot^{\circ}\text{C}
  • Universal gas constant, R=8.36 J/molCR = 8.36\text{ J/mol}\cdot^{\circ}\text{C}

2. Conversion of RR into calories: Using the standard conversion factor 1 cal=4.18 J1\text{ cal} = 4.18\text{ J}: R=8.36 J/molC4.18 J/cal=2 cal/molCR = \frac{8.36\text{ J/mol}\cdot^{\circ}\text{C}}{4.18\text{ J/cal}} = 2\text{ cal/mol}\cdot^{\circ}\text{C}

3. Molar Specific Heat at Constant Volume (CvC_v): Using Mayer's relation: CpCv=RC_p - C_v = R Cv=CpR=82=6 cal/molCC_v = C_p - R = 8 - 2 = 6\text{ cal/mol}\cdot^{\circ}\text{C}

4. Change in Temperature (ΔT\Delta T): ΔT=T2T1=20C10C=10C\Delta T = T_2 - T_1 = 20\,^{\circ}\text{C} - 10\,^{\circ}\text{C} = 10\,^{\circ}\text{C}

5. Change in Internal Energy (ΔU\Delta U): The change in internal energy for an ideal gas is given by: ΔU=nCvΔT\Delta U = n C_v \Delta T

Substituting the values: ΔU=5×6×10=300 calories\Delta U = 5 \times 6 \times 10 = 300\text{ calories}

Final Answer: The change in the internal energy of the gas is 300 calorie300\text{ calorie}.

Calculate Internal Energy Change for Gas Heated at Constant Volume | Physics PYQ Solution - JEE Challenger