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Calculate Heat Required for Temperature Dependent Specific Heat Capacity

The specific heat capacity of a substance is temperature dependent and is given by the formula C=kTC = kT, where kk is a constant of suitable dimensions in SI units, and TT is the absolute temperature. If the heat required to raise the temperature of 1 kg1\text{ kg} of the substance from 73C-73^\circ\text{C} to 27C27^\circ\text{C} is nknk, the value of nn is ______.

[Given: 0 K=273C0\text{ K} = -273^\circ\text{C}.]

Official Numerical Answer25000

Step-by-Step Solution

To find the value of nn, we start by expressing the infinitesimal amount of heat dQdQ required to raise the temperature of a mass mm of the substance by dTdT:

dQ=mCdTdQ = m C \, dT

Given that the mass of the substance is m=1 kgm = 1\text{ kg} and its specific heat capacity is C=kTC = kT, the equation simplifies to:

dQ=(1 kg)(kT)dT=kTdTdQ = (1\text{ kg}) \cdot (kT) \, dT = kT \, dT

Next, we convert the initial and final temperatures from degrees Celsius to Kelvin using 0 K=273C0\text{ K} = -273^\circ\text{C}:

T1=73C=73+273=200 KT_1 = -73^\circ\text{C} = -73 + 273 = 200\text{ K} T2=27C=27+273=300 KT_2 = 27^\circ\text{C} = 27 + 273 = 300\text{ K}

The total heat QQ required to raise the temperature from T1T_1 to T2T_2 is obtained by integrating dQdQ over the temperature range:

Q=T1T2kTdT=k[T22]200300Q = \int_{T_1}^{T_2} kT \, dT = k \left[ \frac{T^2}{2} \right]_{200}^{300}

Substitute the limits of integration:

Q=k2(30022002)Q = \frac{k}{2} \left( 300^2 - 200^2 \right) Q=k2(9000040000)Q = \frac{k}{2} \left( 90000 - 40000 \right) Q=k2×50000=25000kQ = \frac{k}{2} \times 50000 = 25000k

We are given that the heat required is equal to nknk:

Q=nk=25000kQ = nk = 25000k

Comparing both sides gives:

n=25000n = 25000

Calculate Heat Required for Temperature Dependent Specific Heat Capacity | Physics PYQ Solution - JEE Challenger